Consider two infinite large parallel current carrying sheet. Current unit width in both sheets is `(1)/(sqrt(pi))A//m`. If direction of current in both sheets is same than force per unit area on each sheet will be :

Options

A. `10^(-7)N//m^(2)`
B. `0.5xx10^(-7)N//m^(2)`
C. `2xx10^(-7)N//m^(2)`
D. `10^(-5)N//m^(2)`

Explanation

To solve the problem of finding the force per unit area on each sheet due to the magnetic field created by the other sheet, we can follow these steps:

### Step 1: Understand the Magnetic Field due to a Current-Carrying Sheet
For an infinite sheet carrying a current density \( k \) (current per unit width), the magnetic field \( B \) produced by the sheet is given by the formula:
\[ B = \frac{\mu_0 k}{2} \]
where \( \mu_0 \) is the permeability of free space.
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