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The time when the voltage drop across th...

The time when the voltage drop across the resistor drops to nearly `37%` of the value just after the switch `S_(w)` is closed : `(R=100k Omega, C = 1 mu F)` is :

A

a. `0.15 s`

B

b. `0.30 s`

C

c. `0.45 s`

D

d. `0.60 s`

Text Solution

Verified by Experts

`tau=RC=(3)/(20)s`
voltage in capacitor rises to `63%` of maximum value
`0.63=(1-e^(t//tau))`
`t=0.15s`
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