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In the circuit shown in figure, the rati...

In the circuit shown in figure, the ratio of currents `i_(1)//i_(2)` is

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potentials are indicated in figure
Current in `2Omega=(10-(-5))/(2)=(15)/(2)=7.5A` , leftwards
Current in `30Omega=(10-(-15))/(30)=(25)/(30)=(5)/(6)A` , downwards
`(i_(1))/(i_(2))=9`
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