A galvanometer measures current which passes through it. A galanometer can measure typically carrent of order of mA. To be able to measure currents of the order of amperes of main current, a shunt resistance 'S' is connected in parallel with galvanometer.
If resistance of galavonometer is `10Omega` and maximum current `i_(g)` is 10mA then the shunt resistance required so that the main current 'I' can be upto 1A is (in `Omega`)

Options

A. `(99)/(10)`
B. `(10)/(99)`
C. 990
D. `(99)/(1000)`

Explanation

To find the shunt resistance \( S \) required for the galvanometer to measure a maximum current of 1 A, we can follow these steps:

### Step 1: Understand the Circuit Configuration
The galvanometer (with resistance \( G \)) and the shunt resistance \( S \) are connected in parallel. The total current \( I \) splits into two parts: the current through the galvanometer \( I_g \) and the current through the shunt \( I_s \).

### Step 2: Write the Current Relationship
According to Kirchhoff's current law, we have:
\[
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