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A particle moving with velocity (2hati-3...

A particle moving with velocity `(2hati-3hatj)` m/s collides with a surface at rest in xz–plane as shown in figure and moves with velocity `(2hati+2hatj)` m/s after collision. Then coefficient of restitution is :

A

`2/3`

B

1

C

`sqrt(8/13)`

D

`4/5`

Text Solution

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`e=(v_(sep))/(v_(opp))=2/3`
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