Two blocks of masses `m_(1) = 10 kg` and `m_(2) = 20 kg` are connected by a spring of stiffness k = 200 N/m. The coefficient of friction between the blocks and the fixed horizontal surface is `mu = 0.1`. Find the minimum constant horizontal force F (in Newton) to be applied to m1 in order to slide the mass `m_(2)`. (Take `g = 10 m//s^(2)`)

Explanation

To find the minimum constant horizontal force \( F \) that needs to be applied to mass \( m_1 \) in order to slide mass \( m_2 \), we will go through the following steps:

### Step 1: Calculate the normal forces on both blocks
The normal force \( N_1 \) acting on block \( m_1 \) and \( N_2 \) acting on block \( m_2 \) can be calculated using the formula:
\[ N_1 = m_1 g \]
\[
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