In a series LR circuit, the voltage drop across inductor is 8 volt and across resistor is 6 volt. Then voltage applied and power factor of circuit respectively are:

Options

A. 14V,0.8
B. 10V,0.8
C. 10 V,0.6
D. 14 V,0.6

Explanation

To solve the problem, we need to find the applied voltage and the power factor of a series LR circuit where the voltage drop across the inductor (V_L) is 8 volts and the voltage drop across the resistor (V_R) is 6 volts.

### Step-by-Step Solution:

1. **Identify the given values:**
- Voltage drop across the inductor, \( V_L = 8 \, \text{V} \)
- Voltage drop across the resistor, \( V_R = 6 \, \text{V} \)

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