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In a YDSE, distance between the slits an...

In a YDSE, distance between the slits and the screen is 1m, separation between the slits is 1mm and the wavelength of the light used is `5000nm`. The distance of `100^(th)` maxima from the central maxima is:

A

0.5 m

B

0.577 m

C

0.495 m

D

does not exist

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AI Generated Solution

To find the distance of the 100th maxima from the central maxima in a Young's Double Slit Experiment (YDSE), we can use the formula for the position of the maxima on the screen. ### Step-by-Step Solution: 1. **Identify the given values:** - Distance between the slits and the screen (D) = 1 m - Separation between the slits (d) = 1 mm = \(1 \times 10^{-3}\) m - Wavelength of light (λ) = 5000 nm = \(5000 \times 10^{-9}\) m ...
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