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A wire shaped as a semicircle of radius ...

A wire shaped as a semicircle of radius a, is rotating about an acis PQ with a constant angular velocity `omega = 1/sqrt(LC)`, with the help of an external agent. A uniform magnetic field B exists in space and is directed into the plane of the figure. (circuit part remains at rest) (left part is at rest)

A

The rms value of current in the circuit is `(piBa^(2))/(Rsqrt(2LC))`

B

The rms value of current in the circuit is `(piBa^(2))/(2Rsqrt(2LC))`

C

The maximum energy stored in the capacitor is `(pi^(2)B^(2)a^(4))/(8 R^(2)C)`

D

The maximum power delivered by the external agent is `(pi^(2)B^(2)a^(4))/(4LCR)`

Text Solution

Verified by Experts

Let at time t the angle between magnetic field and area vector (semicircle) be `theta`, then `theta=wt`
`phi=vec(B).vec(S)=(pia^(2)B)/2 cos omega t`.
`epsilon=-(dphi)/(dt)=(piBa^(2)omega)/2 sin omega t`
`epsilon_(0) =(piBa^(2))/(2sqrt(LC))` peak emf
Since the circuit is in resonance
`|z|=RrArr i_(0)=(piBa^(2))/(2Rsqrt(LC))` peak current
`i_(rms)=(i_(0))/(sqrt(2))rArr i_(rms)=(piBa^(2))/(2Rsqrt(2LC))`
`U_(C)=1/2 CV_(0)^(2)to `max. energy `V_(0)to` peak voltage
`V_(0) =i_(0)X_(c)=(i_(0))/(C omega)=(i_(0)sqrt(LC))/C`
`U_(C)=1/2 Cxx(pi^(2)B^(2)a^(4))/(4R^(2) C^(2))=(pi^(2)B^(2)a^(4))/(8R^(2)C)`
`P_(ext). =P_("Dissipated")=epsilon_(0)i_(0)=(piBa^(2))/(2sqrt(LC))xx(piBa^(2))/(2Rsqrt(LC)), P_(Ext)=(pi^(2)B^(2)a^(4))/(4LCR)`
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