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A body is thrown with a velocity of 9.8 ...

A body is thrown with a velocity of 9.8 m/s making an angle of `30^(@)` with the horizontal. It will hit the ground after a time

A

40 mV

B

60 mV

C

80 mV

D

zero

Text Solution

Verified by Experts

Explanation :
Perpendicular distance between CD and O is 20 cm .
There fore, induced emf in CD
`=d/2I(dB)/(dt)=20/2xx10^(-2)xx20xx10^(-2)xx2`
`=40 mV`
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