A `20gm` particle is subjected to two simple harmonic motions
`x_(1)=2 sin 10t,`
`x_(2)=4 sin (10t+(pi)/(3))`, where `x_(1) & x_(2)` are in metre `& t ` is in `sec`.

Options

A. The displacement of the particle at t=0 will be `2sqrt(3)m`
B. Maximum speed of the particle will be `20sqrt(7) m//s`.
C. Magnitude of maximum acceleration of the particle will be `200sqrt(7) m//s^(2)`
D. Energy of the resultant simple harmonic motion will be 28 J

Explanation

To solve the problem step by step, we need to analyze the two simple harmonic motions given and find the resulting displacement, amplitude, maximum speed, and energy of the motion.

### Step 1: Calculate the displacement at \( t = 0 \)

Given the equations of motion:
- \( x_1 = 2 \sin(10t) \)
- \( x_2 = 4 \sin(10t + \frac{\pi}{3}) \)

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