Home
Class 12
PHYSICS
A ring of radius r made of wire of densi...

A ring of radius `r` made of wire of density `rho` is rotated about a stationary vertical axis passing through its centre and perpendicular to the plane of the ring as shown in the figure. Determine the angular velocity (in rad/s) of ring at which the ring breaks. The wire breaks at tensile stress `sigma`. Ignore gravity. Take `sigma//rho = 4` and `r= 1 m.`

Text Solution

Verified by Experts

`2T sin (Delta theta)/2 =dm xxomega^(2)r`
`2T((Delta theta)/2)=rhoxxAxxr Delta thetaxxomega^(2)xxr`
`sigma =T/A=rho^(2) omega^(2)`
`:. omega=1/rsqrt((sigma)/(rho))` = 2 rad/sec
Promotional Banner

Topper's Solved these Questions

  • NUCLEAR PHYSICS

    RESONANCE ENGLISH|Exercise Advanced level solutions|16 Videos
  • SEMICONDUCTORS

    RESONANCE ENGLISH|Exercise Exercise 3|88 Videos

Similar Questions

Explore conceptually related problems

Moment of inertia of a ring of mass M and radius R about an axis passing through the centre and perpendicular to the plane is

A ring of mass m and radius r rotates about an axis passing through its centre and perpendicular to its plane with angular velocity omega . Its kinetic energy is

A circular ring of radius R and mass m made of a uniform wire of cross sectional area A is rotated about a stationary vertical axis passing throgh its centre and perpendicular to the plane of the ring. If the breaking stress of the material of the ring is sigma_(b) , then determine the maximum angular speed omega_("max") at which the ring may be rotated without failure.

The moment of inertia of a circular ring of mass 1 kg about an axis passing through its centre and perpendicular to its plane is "4 kg m"^(2) . The diameter of the ring is

A ring of mass 10kg and diameter 0.4m is rotated about an axis passing through its centre. If it makes 1800 revolutions per minute then , the angular momentum of the ring is

The moment of inerta of a ring of mass 1kg about an axis passing through its centre perpendicular to its surface is 4kgm^(2) . Calculate the radius of the ring.

The moment of inerta of a ring of mass 1kg about an axis passing through its centre perpendicular to its surface is 4kgm^(2) . Calculate the radius of the ring.

A charge q is unifomly distrybuted over a nonconducting ring of radius R. The ring is rotated about an axis passing through its centre and perpendicular to the plane of the ring with frequency f. The ratio of electric potential to the magnetic field at the centre of the ring depends on.

A ring of radius R is made of a thin wire of material of density rho having cross section area a. The ring rotates with angular velocity omega about an axis passing through its centre and perpendicular to the plane. If we consider a small element of the ring,it rotates in a circle. The required centripetal force is provided by the component of tensions on the element towards the centre. A small element of length dl of angular width d theta is shown in the figure. If T is the tension in the ring, then

A ring of radius R is made of a thin wire of material of density rho having cross section area a. The ring rotates with angular velocity omega about an axis passing through its centre and perpendicular to the plane. If we consider a small element of the ring,it rotates in a circle. The required centripetal force is provided by the component of tensions on the element towards the centre. A small element of length dl of angular width d theta is shown in the figure. If for a given mass of the ring and angular velocity, the radius R of the ring is increased to 2R , the new tension will be

RESONANCE ENGLISH-REVISION DPP-All Questions
  1. A solid sphere (radius = R) rolls without slipping in a cylindrical th...

    Text Solution

    |

  2. Two opposite forcesF(1) = 120 N and F(2) = 80 N act on an elastic plan...

    Text Solution

    |

  3. A ring of radius r made of wire of density rho is rotated about a stat...

    Text Solution

    |

  4. The length of an elastic string is 5 metre when the longitudinal tensi...

    Text Solution

    |

  5. A block of mass m=2kg of shown dimensions is placed on a plank of mass...

    Text Solution

    |

  6. There are two ideal springs of force constants K1 and K2 respectively....

    Text Solution

    |

  7. There are two ideal springs of force constants K1 and K2 respectively....

    Text Solution

    |

  8. There are two ideal springs of force constants K1 and K2 respectively....

    Text Solution

    |

  9. A rod of mass 'm and length L is attached to a L shaped plank at 'A'. ...

    Text Solution

    |

  10. A rod of mass 'm and length L is attached to a L shaped plank at 'A'. ...

    Text Solution

    |

  11. A rod of mass 'm and length L is attached to a L shaped plank at 'A'. ...

    Text Solution

    |

  12. Two blocks A and B of masses m and 2m are placed on a smooth horizonta...

    Text Solution

    |

  13. A uniform rod of mass M and length L, area of cross section A is place...

    Text Solution

    |

  14. A uniform rod of mass M and length L, area of cross section A is place...

    Text Solution

    |

  15. In Young's double slit experiment, the distance between two slits is m...

    Text Solution

    |

  16. A particle of mass m = 1 kg excutes SHM about mean position O with ang...

    Text Solution

    |

  17. In a spring block system on a horizontal smooth surface. K = spring co...

    Text Solution

    |

  18. A container open from top, filled with water (density rhow) upto the t...

    Text Solution

    |

  19. A uniform solid sphere of radius R is in equilibrium inside a liquid w...

    Text Solution

    |

  20. A large open tank is filled with water upto a height H. A small hole i...

    Text Solution

    |