A particle of mass m is projected form ground with velocity u making angle `theta` with the vertical. The de Broglie wavelength of the particle at the highest point is

Options

A. `oo`
B. `h/(m u sin theta)`
C. `h/(m u cos theta)`
D. `h/(m u)`

Explanation

(C) velocity at highest point `= u sin theta`.
`:. lambda_(d)=h/(m u sin theta)` (Since `theta` is angle between velocity and vertical)