X-rays of high penetrating power are called hard X-ray. Hard X-rays have energy of the order of `10^5 eV`. The minimum potential difference through which the electrons should be accelerated in an X-ray tube to obtain X-ray of energy `10^5eV` is:

Options

A. `2xx10^(5) V`
B. 50 kV
C. 40 kV
D. `10^(5) V`

Explanation

To find the minimum potential difference required to obtain X-rays of energy \(10^5 \, \text{eV}\), we can use the relationship between energy and potential difference.

### Step-by-Step Solution:

1. **Understanding the Relationship**:
The energy gained by an electron when it is accelerated through a potential difference \(V\) is given by the formula:
\[
E = eV
...