Radius of a nucleus is given by the relation `R = R_(0)A^(1//3)` where `R_(0) = 1.3 xx 10^(-15) m` and A is mass number. For a nucleon inside a nucleus, de-Broglie wavelength is given by diameter of the nucleus. Average kinetic energy of a nucleon in the `Te^(128)` nucleus based on above information will be :

Options

A. 4.7 MeV
B. 10 MeV
C. 2 MeV
D. 12 MeV

Explanation

To solve the problem, we will follow these steps:

### Step 1: Calculate the radius of the nucleus
The radius \( R \) of the nucleus is given by the formula:
\[ R = R_0 A^{1/3} \]
where \( R_0 = 1.3 \times 10^{-15} \, \text{m} \) and \( A = 128 \) (mass number of \( Te^{128} \)).
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