X-ray from a tube with a target `A` of atomic number `Z` shows strong `K` lines for target `A` and weak`K` lines for impurities. The wavelength og `K_(alpha)` lines is `lambda_(z)` for target `A` and `lambda_(1) and lambda_(2)` for two impurities.
`(lambda_(z))/(lambda_(1)) = 4 and (lambda_(z))/(lambda_(2)) = (1)/(4)`
Assuming the screeining contant of `K_(alpha)` lines to be unity select the correct statement(s).

Options

A. The atomic number of first impurity is 2Z-1
B. The atomic number of first impurity is 2Z+1
C. The atomic number of first impurity is `(Z+1)/2`
D. The atomic number of second impurity is Z/2+1

Explanation

To solve the problem, we will analyze the given information step by step using the relationship between the wavelength of X-rays and the atomic number of the target material.

### Step 1: Understand the relationship between wavelength and atomic number
According to Moseley's Law, the frequency of X-ray emitted is related to the atomic number (Z) of the element. The relationship can be expressed as:
\[ \sqrt{\nu} = A(Z - B) \]
where \( \nu \) is the frequency, \( A \) and \( B \) are constants. For K lines, we can assume \( B = 1 \).
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