A rope, under tension of `200N` and fixed at both ends, oscialltes in a second harmonic standing wave pattern. The displacement of the rope is given by `y=(0.10)sin ((pix)/(3)) sin (12 pit)`, where `x=0` at one end of the rope, `x` is in metres and `t` is in seconds. Find the length of the rope in metres.

Explanation

`y=0.10 sin ((pix)/3)sin(12pit)`
`k=pi/3 rArr lambda=6m`
Length of the rope =`lambda=6m`
`y=4 sin ((pix)/15)cos(96 pit)=2 sin ((pix)/15+ 96pit)+2 sin ((pix)/15-96pit)`