The ratio of translational and rotational kinetic energies at `100K` temperature is `3:2`. Then the internal energy of one mole gas at that temperature is `(R=8.3j//"mol"-K]`

Options

A. `1175J`
B. `1037.5J`
C. `2075J`
D. `4150J`

Explanation

To find the internal energy of one mole of gas at a temperature of 100 K, given the ratio of translational and rotational kinetic energies is 3:2, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Ratio of Kinetic Energies**:
- The ratio of translational kinetic energy (TKE) to rotational kinetic energy (RKE) is given as 3:2.
- Let TKE = 3x and RKE = 2x for some value x.

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