The state of an ideal gas is changed through an isothermal process at temperature `T_(0)` as shown in the figure. The work done by the gas in going from state B to C is double the work done by the gas in going from state A to B. IF the pressure in the state B is `p_(0)//2`, then the pressure of the gas in state C is

Options

A. `(P_(0))/(2)`
B. `(P_(0))/(4)`
C. `(P_(0))/(6)`
D. `(P_(0))/(8)`

Explanation

Work done by gas in going isothermally from state `A` to `B` is
`DeltaW_(AB)=nRT"ln"(P_(A))/(P_(C))=nRTln2` .....(1)
Work done by gas in going isothermally from state `B` to `C` is
`DeltaW_(BC)=nRT"ln"(P_(B))/(P_(C))=nRT"ln"(P_(0))/(2P_(C))`.....(2)
It is given that `DeltaW_(BC)=2 DeltaW_(AB)`
`therefore "ln"(P_(0))/(2P_(C))=ln(2)^(2) therefore P_(c)=(P_(0))/(8)`