A stationary observer receives a sound from a source of frequency `2000Hz` moving with constant velocity. The apparent frequency varies with as shown in the figure

The value of `f_(m)` is `(2300-10x)Hz`. Find the value of `x`. (Take speed of sound `=30m//s` and neglect the time taken by sound to reach the stationary observer).

Explanation

`t_(m)=(v)/((v-v_(s)costheta)_("min"))xxf`
`1800=(v)/((v+v_(s)costheta)_("min"))xxf`
On solving
`f_(m)=2250 Hz`
`=2300-50`