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One mole of a diatomic gas is heated und...

One mole of a diatomic gas is heated under a "kibolinsky process" in which gas pressure is temperature controlled according to law `P=(4)/(5)CT^(3//2)`. Where `C` is kibolinsky constant. In this process, gas is heated by `300K` temperature. Answer the following questions.
Under above a process the molar specific heat of gas is:

A

`(R)/(2)`

B

`R`

C

`2R`

D

None of these

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AI Generated Solution

To find the molar specific heat of the diatomic gas under the given "kibolinsky process," we can follow these steps: ### Step 1: Understand the Process The problem states that the pressure \( P \) is related to temperature \( T \) by the equation: \[ P = \frac{4}{5} C T^{\frac{3}{2}} \] where \( C \) is a constant. We also know that the gas is heated by \( 300 \, K \). ...
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