A force of constant magnitude F acts on a particle moving in a plane such that it is perpendicular to the velocity `vecv(|vecv|=v)` of the body and the force is always direct towards a fixed point. Then the angle turned by the velocity vector of the particle as it covers a distance S is (take mass of the particle as m)

Options

A. `(FS)/(2mv^(2))`
B. `(2FS)/(mv^(2))`
C. `(FS^(2))/(mv)`
D. `(FS)/(mv^(2))`

Explanation

Since `vecFbotvecV` the particle will move along a circle
`thereforeF=(mv^(2))/(R)&theta=(S)/(R)impliestheta=(FS)/(mv^(2))`