Anhydrous white solid `(A)` on addition of potassium iodine solution gave a brown precipitate which turned white `(B)` on addition
of excees of hypo solution. When potasium cyanide is added to an
aqeous Solution of `(A)`a white precipitate is formed which then dissolved in excess forming `(C )`
A Solution `(%)` of `(A)` on adding to a solution of white portion of
egg produced violet colouration in alkaline medium `(i.e)` in
presence of `NaOH)` identify compound `(A)` and explain the reactions.

Explanation

To solve the problem, we need to identify the compound (A) and explain the reactions involved. Let's break it down step by step.

### Step 1: Identify Compound (A)
The problem states that anhydrous white solid (A) reacts with potassium iodide (KI) to form a brown precipitate. This suggests that (A) is likely a copper salt, specifically copper(II) sulfate (CuSO4), as it is a white solid.

### Step 2: Reaction with Potassium Iodide
When potassium iodide is added to copper(II) sulfate, a brown precipitate is formed. The reaction can be represented as follows:

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