Statement: The number of unpaired electrons in the following gaseous ion:
`Mn^(3+),Cr^(3+),V^(3+) and Ti^(3+)` are `4,3,2` and 1 respectively
Statement: `Cr^(3+)`is most stable in aqeous solution among these ions.

Options

A. Statement-1 is true, Statement-2 is True, Statement-2 is a correct explanation for statement-1
B. Statement-1 is true, Statement-2 is True, Statement-2 is Not a correct explanation for statement-1
C. Statement-1 is true, Statement-2 is False
D. Statement-1 is False, Statement-2 is True

Explanation

To solve the question regarding the number of unpaired electrons in the ions \( \text{Mn}^{3+}, \text{Cr}^{3+}, \text{V}^{3+}, \text{Ti}^{3+} \) and the stability of \( \text{Cr}^{3+} \) in aqueous solution, we will follow these steps:

### Step 1: Determine the electronic configurations of the ions

1. **Manganese (\( \text{Mn}^{3+} \))**:
- Atomic number of Mn = 25
- Electronic configuration: \( [\text{Ar}] 4s^2 3d^5 \)
- For \( \text{Mn}^{3+} \), we remove 3 electrons (2 from \( 4s \) and 1 from \( 3d \)):
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