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Which is the last element in the series of the actinoids? Write the electronic configuration of this element. Comment on the possible oxidation state of this element.

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The correct Answer is:
Last actinoids=Lawrencium`(Z=103)`
Electronic configuration =`[Rn]5f^(14),6d^(1),7S^(2)`
Possible oxidation state=`+3`
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RESONANCE ENGLISH-D BLOCK ELEMENTS-BOARD LEVEL EXERCISE
  1. Why is the highest oxidation state of a metal exhibited in its oxide o...

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  2. Name the oxometal anions of the first series of the transition metals ...

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  3. Which metal in the first series of transition metals exhibits +1 oxida...

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  4. Which is a stronger reducing agent Cr^(2+)or Fe^(2+) and why ?

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  5. for the first series of transition metal the E^(0) (Theta) Value are E...

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  6. Determine the magnetic moment of a divalent ion in aqueous solution if...

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  7. The E^(0)(M^(2+)//M) value for copper is positive (+0.34V). What is po...

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  8. Why are Mn^(2+) compounds more stable than Fe^(2+) towards oxidation t...

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  9. Explain briefly how +2 state becomes more and more stable in the first...

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  10. The chemistry of the actinoid elements is not so smooth as that of the...

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  11. Which is the last element in the series of the actinoids? Write the el...

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  12. What are alloys? Name an important alloy which contains some of the la...

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  13. How is the variability in oxidation states of transition metals differ...

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  14. Descibe the oxidising actions of potassium dichromate and write the io...

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  15. Name the members of the lanthanoid series which exhibit +4 oxidation s...

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  16. How would you account for the irregular variation of ionization enthal...

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  17. How would you account for the following : (i) Out of the d^(4) speci...

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  18. Compare the chemistry of actinoids with that of the lanthanoids with s...

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  19. In what way is the electronic configuration of the transition elements...

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  20. E(Mn^(3+)//Mn^(2+))^@is highly positive than that of E(Cr^(3+)//Cr^(2+...

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