When acidified solution of `K_(2)Cr_(2)O_(7)` is shaken with aqeous solution of `FeSO_(4)`, Then:

Options

A. `Cr_(2)O_(7)^(2-) ` ions is reduced to `Cr^(3+)` ions
B. `Cr_(2)O_(7)^(2-)` ion is converted to `CrO_(4)^(2-)` ion
C. `Cr_(2)O_(7)^(2-)` ions is reduced to `Cr`
D. `Cr_(2)O_(7)^(2-)` ions is converted to `CrO_(3)`

Answer

To solve the question regarding the reaction between acidified potassium dichromate (K₂Cr₂O₇) and ferrous sulfate (FeSO₄), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Acidified potassium dichromate (K₂Cr₂O₇)
- Aqueous ferrous sulfate (FeSO₄)

### Step 2: Understand the Oxidation States
In potassium dichromate (K₂Cr₂O₇), chromium (Cr) is in the +6 oxidation state. In ferrous sulfate (FeSO₄), iron (Fe) is in the +2 oxidation state.

### Step 3: Write the Reaction
When K₂Cr₂O₇ is mixed with FeSO₄ in an acidic medium, the reaction can be represented as:
\[ K_2Cr_2O_7 + FeSO_4 + H_2SO_4 \rightarrow K_2SO_4 + Fe_2(SO_4)_3 + Cr_2(SO_4)_3 + H_2O \]

### Step 4: Identify the Changes in Oxidation States
- Chromium (Cr) in K₂Cr₂O₇ is reduced from +6 to +3.
- Iron (Fe) in FeSO₄ is oxidized from +2 to +3.

### Step 5: Determine the Products
The chromium from K₂Cr₂O₇ is reduced to Cr³⁺ ions. Therefore, the main product of the reduction of Cr in this reaction is Cr³⁺.

### Conclusion
When acidified K₂Cr₂O₇ is shaken with aqueous FeSO₄, the chromium in K₂Cr₂O₇ is reduced to Cr³⁺ ions.

### Final Answer
Cr₂O₇²⁻ is reduced to Cr³⁺ ions.

---