`CrO_(3)` dissolved in aqueous `NaOH` to give:

Options

A. `CrO_(4)^(2-)`
B. `Cr(OH)_(3)`
C. `Cr_(2)O_(7)^(2-)` ions is reduced to `Cr`
D. `Cr(OH)_(2)`

Explanation

To solve the question of what product is formed when CrO₃ is dissolved in aqueous NaOH, we can follow these steps:

### Step 1: Write the Reactants
We start with the reactants given in the question:
- Chromium trioxide (CrO₃)
- Sodium hydroxide (NaOH)

### Step 2: Write the Chemical Reaction
When CrO₃ reacts with NaOH, the reaction can be represented as:
\[ \text{CrO}_3 + \text{NaOH} \rightarrow \text{Na}_2\text{CrO}_4 + \text{H}_2\text{O} \]

### Step 3: Balance the Reaction
To balance the reaction, we need to ensure that the number of atoms of each element is the same on both sides of the equation. In this case, we need to add coefficients to balance the sodium (Na) and hydroxide (OH) ions:
\[ \text{CrO}_3 + 2 \text{NaOH} \rightarrow \text{Na}_2\text{CrO}_4 + \text{H}_2\text{O} \]

### Step 4: Identify the Products
From the balanced equation, we can see that the products of the reaction are:
- Sodium chromate (\( \text{Na}_2\text{CrO}_4 \))
- Water (\( \text{H}_2\text{O} \))

### Step 5: Write the Ionic Form of the Product
The sodium chromate can be expressed in ionic form as:
\[ 2 \text{Na}^+ + \text{CrO}_4^{2-} \]

### Step 6: Conclusion
Thus, when CrO₃ is dissolved in aqueous NaOH, the main product formed is the chromate ion (\( \text{CrO}_4^{2-} \)) along with sodium ions (\( \text{Na}^+ \)).

### Final Answer
The correct answer to the question is that CrO₃ dissolved in aqueous NaOH gives \( \text{CrO}_4^{2-} \) ions.

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