An aqueous solution of inorganic compounds (X) gives following reactions.
(i) With an aqueous solution of barium chloride a precipitate insoluble in dilute `HCl` is obtained.
(ii) Addition of excess of `Kl` gives a brown precipitate which turns white on additon of excess of hyposolution.
(iii) With an aqueous solution of `K_(4)[Fe(CN)_(6)]`, a brown coloured precipitate is obtained.
Identity (X) and gives equation for the reaction for (i),(ii) and (iii) observations.

Answer

`X=CuSO_(4)`

Explanation

(Step (i) suggested that compound (X) contain `SO_(4)^(2-)` redical.
(ii) step (ii) suggested that the compound (X) contain `Cu^(2+)` radical.
Reaction
(i) `CuSO_(4)(X)+BaCl_(2) to BaSO_(4)downarrow("white")+CuCl_(2),BaSO_(4)` is insolule in `HCl`
(ii) `2CuSO_(4)(X)+4KIto2CuI_(2)+2K_(2)SO_(4)`
`2CuI_(2)("unstable") to 2Cu_(2)I_(2)downarrow("white")+I_(2)uparrow`
`I_(2)+2Na_(2)S_(2)O_(3) toNa_(2)S_(4)O_(6)("colourless")+2NaI("colourless")`
`2CuSO_(4)(X)+K_(4)[CN)_(6)] to Cu_(2)[Fe(CN)_(6)]downarrow("Brown")+2K_(2)SO_(4)`