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Complete and balance the following equat...

Complete and balance the following equation:
`Ag_(2)S+CuCl_(2)+Hg....…...+……..+S+2Ag`

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To complete and balance the equation: **Given Reaction:** \[ \text{Ag}_2\text{S} + \text{CuCl}_2 + \text{Hg} \rightarrow \text{...?} + \text{...?} + \text{S} + 2\text{Ag} \] ### Step 1: Identify the Products The reactants are silver sulfide (\( \text{Ag}_2\text{S} \)), copper(II) chloride (\( \text{CuCl}_2 \)), and mercury (\( \text{Hg} \)). When these react, the products formed are: - Mercury(I) chloride (\( \text{Hg}_2\text{Cl}_2 \)) - Copper(I) chloride (\( \text{CuCl} \)) - Sulfur (\( \text{S} \)) - Silver (\( \text{Ag} \)) Thus, the complete reaction is: \[ \text{Ag}_2\text{S} + \text{CuCl}_2 + \text{Hg} \rightarrow \text{Hg}_2\text{Cl}_2 + 2\text{CuCl} + \text{S} + 2\text{Ag} \] ### Step 2: Write Down the Unbalanced Equation Now we can write the unbalanced equation: \[ \text{Ag}_2\text{S} + \text{CuCl}_2 + \text{Hg} \rightarrow \text{Hg}_2\text{Cl}_2 + \text{CuCl} + \text{S} + 2\text{Ag} \] ### Step 3: Count Atoms on Both Sides Now, we need to count the number of atoms of each element on both sides of the equation to balance it. **Reactants:** - Ag: 2 - S: 1 - Cu: 1 - Cl: 2 - Hg: 1 **Products:** - Ag: 2 - S: 1 - Cu: 2 - Cl: 2 - Hg: 2 ### Step 4: Balancing the Equation 1. **Silver (Ag)**: Already balanced (2 on both sides). 2. **Sulfur (S)**: Already balanced (1 on both sides). 3. **Copper (Cu)**: We have 1 in reactants and 2 in products. So, we need to adjust the copper in the reactants. - Change \( \text{CuCl}_2 \) to \( 2\text{CuCl}_2 \). 4. **Chlorine (Cl)**: Now we have 4 Cl in reactants (from \( 2\text{CuCl}_2 \)) and 2 in products. So we need to adjust the \( \text{CuCl} \) in products. - Change \( \text{CuCl} \) to \( 2\text{CuCl} \). 5. **Mercury (Hg)**: We have 1 in reactants and 2 in products. So we need to adjust the mercury in reactants. - Change \( \text{Hg} \) to \( 2\text{Hg} \). Now, the balanced equation looks like this: \[ \text{Ag}_2\text{S} + 2\text{CuCl}_2 + 2\text{Hg} \rightarrow \text{Hg}_2\text{Cl}_2 + 2\text{CuCl} + \text{S} + 2\text{Ag} \] ### Final Balanced Equation The final balanced equation is: \[ \text{Ag}_2\text{S} + 2\text{CuCl}_2 + 2\text{Hg} \rightarrow \text{Hg}_2\text{Cl}_2 + 2\text{CuCl} + \text{S} + 2\text{Ag} \]
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RESONANCE ENGLISH-D BLOCK ELEMENTS-EXERCISE-2 PART-I
  1. Why is the E^(ϴ) value for the Mn^(3+)//Mn^(2+) couple much more posit...

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  2. Which is a stronger reducing agent Cr^(2+)or Fe^(2+) and why ?

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  3. Explain why Cu^(+) ion is not stable in aqueous solutions?

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  4. The aqueous solution of FeCl(3) is acidic . Why?

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  5. Ferric iodide is very unstable but ferric chloride is not

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  6. Copper dissolves in dilute nitric acid but not in dilute HCl. Why?

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  7. Blue colour of CuSO(4) solution is discharge slowly when an iron rod i...

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  8. Copper (I) ions are not known in aqueous solution.

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  9. Calculate the number of unpaired electrons in the following gaseous io...

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  10. Mercurous ion is written as Hg(2)^(2+) whereas cuprous ion is written ...

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  11. Copper sulphate dissolves in NH(4)OH solution but FeSO(4) does not.

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  12. An aqueous solution of inorganic compounds (X) gives following reactio...

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  13. H(2)S gas is passed through an acidic solution of K(2)Cr(2)O(7) .The s...

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  14. What happen when(i) a small amount of KMnO(4) is added to concentrated...

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  15. A hydrated mettalic salt(A). Light green in colour , on careful heatin...

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  16. A white substance (A) reacts with dilute H(2)SO(4) to produce a colour...

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  17. Write the balanced chemical equation for the following reaction:- Nitr...

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  18. Complete and balance the following equation: Ag(2)S+CuCl(2)+Hg....…....

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  19. Which out of the two ,La(OH)(3) and Lu(OH)(3), is more basic and why?

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  20. One among the lanthanoides, Ce(III), can be easily oxidized to Ce(IV) ...

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