In the neutralization of `Na_(2)S_(2)O_(3)` using `K_(2)Cr_(2)O_(7)` by idometry, the equivalent weight of `K_(2)Cr_(2)O_(7)` is

Options

A. `("molecular weight")//2`
B. `("molecular weight")//6 `
C. `("molecular weight")//3`
D. Same as molecular weight

Answer

B

Explanation

`({:(Cr_(2)O_(7)^(2-)+14H^(+),+6e^(-) rarr2C^r^(3+),+7 H_(2)O),(,2l^(-)rarrI_(2)+2e^(-)x3,):})/({:(Cr_(2)O_(7)^(2-),+14H^(+)+6I^(-)rarr2C^(3+)+3I_(2),+7H_(2)O),(,so eq.wt.=("Molecular weight")/(6),):})`