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Identify (A),(B) and (C). Also explain...


Identify (A),(B) and (C).
Also explain colour difference between `MCl_(4)` and (B).

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The correct Answer is:
(A) is `TiCl_(4)` as it has no unpaired electron and is liguid at room temperature on account of covalent character because of high polarising power of `Ti^(+4). TiCl_(4)` being covalent gets hydrolysed forming `TiO_(2)(H_(2)O)_(2)` and `HCl` (B) which fumes in air.
In `[Ti(H_(2)O)_(6)]Cl_(3)` complex `Ti(III) has one unpaired electron`(3d^(1)) `which gives violet//purple colour due to d-d transition.
`(##RES_INO_CHM_V01_XII_V02_C01_S01_263_A01##)`
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