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Oxidation state of Mn in the compound fo...

Oxidation state of Mn in the compound formed by alkaline oxidative fusion of `MnO_(2)` by KOH is `:`

A

`3` electrons in neutral medium

B

`5` electrons in neutral medium

C

`3` electrons in alkaline medium

D

`5` electrons in acidic medium

Text Solution

Verified by Experts

The correct Answer is:
ACD
in acidic medium,`" "`MnO_(4)^(-)+8H^(+)+5e^(-) to Mn^(2+)+4H_(2)O`
`(V.f=5)`
`"in neutral//faintly alkaline medium"," " `MnO_(4)^(-)+2H_(2)O+3E^(-) to MnO_(2)+4OH^(-)`
(v.f.=3)
"In strong alkaline medium"," " MnO_(4)^(-)+e^(-) to MnO_(4)^(2-)`
(v.f.=1)
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