What would happen when a solution of potassium chromate is treated with an excess of dilute nitric acid?

Options

A. `Cr_(2)O_(7)^(2-)` and `H_(2)O` are formed
B. `CrO_(4)^(2-)` is reduced to `+3` state of `Cr`
C. `CrO_(4)^(2-) ` is oxidised to `0` state of `Cr`
D. `Cr^(3+)` and `Cr_(2)O_(7)^(2-)` are formed

Answer

1

Explanation

`2CrO_(4)^(2-)+2H^(+) to Cr_(2)O_(7)^(2-)+H_(2)O`.