Home
Class 12
CHEMISTRY
8 g of O^(2-) ion has amount of charge e...

8 g of `O^(2-)` ion has amount of charge equal to : `(N_(A) = 6.02xx10^(23) , e = - 1.6xx10^(-19)C)`

A

`5N_(A)eC`

B

`2N_(A)eC`

C

`N_(A)eC`

D

`(1)/(2)N_(A)eC`

Text Solution

Verified by Experts

The correct Answer is:
C
`8 g of O^(2-)` ion has amount …………
Moles of `O^(2) = (8)/(16) = (1)/(2)`mole
Number of `O^(2-)` ions `= (1)/(2)xxN_(A)`
Total Change on `O^(2-) = (1)/(2)xxN_(A)xx2e=N_(A)eC`.
Promotional Banner

Similar Questions

Explore conceptually related problems

Molar mass of electron is nearly : (N_(A) = 6 xx 10^(23)) , mass of e^(-) = 9.1 xx 10^(-31)Kg

The number of atoms in 0.1 mol of a tetraatomic gas is ( N_(A) = 6.02 xx 10^(23) mol^(-1) )

Silver crystallises in a fcc lattice. The edge length of its unit is 4.077xx10^(-8)cm and its density is 10.5g cm^(-3) . Claculate on this basis of the atomic mass of silver (N_(A)=6.02xx10^(23) "mol"^(-1))

An aqueous solution contains 0.10 MH_2 S and 0.20 M HCl if the equilibrium constants for the formation of HS^(-) " from " H_2S " is " 1.0 xx 10^(-7) and " that of " S^(2-) " from " HS^(-) ions is 1.2 xx 10 ^(-13) then the concentration of S^(2-) ions in aqueous solution is 5 xx 10 ^(-8) 3 xx 10 ^(-20) 6 xx 10 ^(-21) 5 xx 10 ^(-19)

If NaCl is doped with 10^(-8)mol% of SrCl_(2) the concentration of cation vacancies will be (N_(A)=6.02xx10^(23)mol^(-1))

If NaCl is doped with 10^(-4)mol% of SrCl_(2) the concentration of cation vacancies will be (N_(A)=6.02xx10^(23)mol^(-1))

The number of atoms in 0.1 mole of a triatomic gas is (N_(A) = 6.02 xx 10^(23) "mol"^(-1))

If light of frequency 8.2xx10^14 Hz is incident on the metal , cut-off voltage for photoelectric emission is 2.03 V.Find the threshold frequency . Given h= 6.63xx10^(-34) Js , e= 1.6xx10^(-19) C.

An element with density 11.2 g cm^(-3) forms a f. c. c. lattice with edge length of 4xx10^(-8) cm. Calculate the atomic mass of the element. (Given : N_(A)= 6.022xx10^(23) mol^(-1)

Bond dissociation on energy of Cl_(2) is 240 kJ/mol. The longest wavelength of photon that can break this bond would be [N_(A)=6xx10^(23), h=6.6xx10^(-34)J/s]