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5.85 g NaCI is dissolved in 1 litre wate...

`5.85 g NaCI` is dissolved in 1 litre water. The total number of ions of `Na^(+)` and `CI^(-)` in 1 mL of this solution will be :

A

`6.02xx10^(19)`

B

`1.2xx10^(22)`

C

`1.2xx10^(20)`

D

`6.02xx10^(20)`

Text Solution

Verified by Experts

The correct Answer is:
C
`5.85 g NaCI` is dissolved in …………
Number of moles of NaCI = Mass/Molar Mass
`= 5.85//58.5`
`= 0.1 mol`
Number of ions `(Na^(+)+Cr)` in 1 L
`= 2xx0.1xx6.02xx10^(23)`
`= 12.04xx10^(22)`
Number of ions in 1 mL `= 12.04xx10^(22)//1000`
`1.2xx10^(20)`
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