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Given the visible green light has a wave...

Given the visible green light has a wavelength of `510` nm then corresponding frequency and wave number are respectively `(C = 3xx10^(8)ms^(-1))` :

A

`5.8xx10^(14)Hz, 0.001nm`

B

`6xx10^(16)Hz, 0.004 nm^(-1)`

C

`5.8xx10^(14)Hz, 0.001 nm^(-1)`

D

`5xx10^(12)Hz, 0.008 nm`

Text Solution

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The correct Answer is:
To solve the problem of finding the corresponding frequency and wave number for the visible green light with a wavelength of 510 nm, we will follow these steps: ### Step 1: Convert Wavelength from Nanometers to Meters The given wavelength (λ) is in nanometers. We need to convert it to meters for our calculations. \[ \lambda = 510 \, \text{nm} = 510 \times 10^{-9} \, \text{m} \] ### Step 2: Use the Speed of Light to Find Frequency We can use the formula that relates the speed of light (C), frequency (ν), and wavelength (λ): \[ \nu = \frac{C}{\lambda} \] Where: - \( C = 3 \times 10^8 \, \text{m/s} \) - \( \lambda = 510 \times 10^{-9} \, \text{m} \) Substituting the values: \[ \nu = \frac{3 \times 10^8 \, \text{m/s}}{510 \times 10^{-9} \, \text{m}} \] Calculating this gives: \[ \nu \approx 5.88 \times 10^{14} \, \text{Hz} \] ### Step 3: Calculate Wave Number The wave number (k) is defined as the reciprocal of the wavelength: \[ k = \frac{1}{\lambda} \] Using the wavelength in meters: \[ k = \frac{1}{510 \times 10^{-9} \, \text{m}} \] Calculating this gives: \[ k \approx 1.96 \times 10^6 \, \text{m}^{-1} \] Alternatively, if we want to express this in terms of nanometers: \[ k = \frac{1}{510 \, \text{nm}} \approx 0.00196 \, \text{nm}^{-1} \] ### Final Answers Thus, the corresponding frequency and wave number for the visible green light are: - Frequency (ν) = \( 5.88 \times 10^{14} \, \text{Hz} \) - Wave number (k) = \( 1.96 \times 10^6 \, \text{m}^{-1} \) or \( 0.00196 \, \text{nm}^{-1} \) ---
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