From a container having 64 g Oxygen, `11.2L` Oxygen gas at STP and `6.022xx10^(23)` Oxygen atoms are removed. Find the mass of the oxygen gas left :

Options

A. zero
B. 32 g
C. 16 g
D. none

Explanation

To solve the problem, we need to find the mass of oxygen gas left in the container after removing certain quantities of oxygen. We'll break this down step by step.

### Step 1: Understand the Given Information
- **Initial mass of oxygen in the container**: 64 g
- **Volume of oxygen gas removed at STP**: 11.2 L
- **Number of oxygen atoms removed**: \(6.022 \times 10^{23}\) atoms

### Step 2: Calculate the Mass of Oxygen Atoms Removed
We know that the atomic mass of oxygen (O) is 16 g/mol. To find the mass of the oxygen atoms removed, we can use Avogadro's number, which is \(6.022 \times 10^{23}\) atoms/mol.

Using the formula:
\[ \text{Mass} = \left(\frac{\text{Number of atoms}}{\text{Avogadro's number}}\right) \times \text{Atomic mass} \]

Substituting the values:
\[ \text{Mass} = \left(\frac{6.022 \times 10^{23}}{6.022 \times 10^{23}}\right) \times 16 \text{ g} = 1 \times 16 \text{ g} = 16 \text{ g} \]

### Step 3: Calculate the Mass of Oxygen Gas Removed from Volume
At STP (Standard Temperature and Pressure), 1 mole of gas occupies 22.4 L. Therefore, we can find the mass of the oxygen gas removed using the volume.

1 mole of O2 (which is 32 g) occupies 22.4 L. Thus, for 11.2 L:
\[ \text{Mass} = \left(\frac{11.2 \text{ L}}{22.4 \text{ L}}\right) \times 32 \text{ g} = 0.5 \times 32 \text{ g} = 16 \text{ g} \]

### Step 4: Total Mass of Oxygen Removed
Now, we have the mass of oxygen removed from both methods:
- From atoms: 16 g
- From volume: 16 g

Total mass of oxygen removed:
\[ \text{Total mass removed} = 16 \text{ g} + 16 \text{ g} = 32 \text{ g} \]

### Step 5: Calculate the Mass of Oxygen Left
Now, we can find the mass of oxygen left in the container:
\[ \text{Mass of oxygen left} = \text{Initial mass} - \text{Total mass removed} \]
\[ \text{Mass of oxygen left} = 64 \text{ g} - 32 \text{ g} = 32 \text{ g} \]

### Final Answer
The mass of oxygen gas left in the container is **32 grams**.

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