The maximum volume at STP is occupied by

Options

A. `12.8` gram `SO_(2)`
B. `0.5` mole of `NO_(2)`
C. `6.023xx10^(22) "molecules of" CH_(4)`
D. `1 "gram molecules of" CO_(2)`

Answer

To solve the question "The maximum volume at STP is occupied by," we need to calculate the volume occupied by different gases under standard temperature and pressure (STP) conditions, which is defined as 273.15 K and 1 atm. At STP, 1 mole of any ideal gas occupies 22.4 liters.

### Step-by-Step Solution:

1. **Identify the Substances and Their Masses**:
- We have the following substances to consider:
- SO₂: 12.8 grams
- NO₂: 0.5 moles
- CH₄: 6.023 x 10²² molecules
- CO₂: 1 gram molecule

2. **Calculate Moles of SO₂**:
- The molecular mass of SO₂ = 32 (for S) + 32 (for O₂) = 64 g/mol.
- Moles of SO₂ = Mass / Molecular Mass = 12.8 g / 64 g/mol = 0.2 moles.
- Volume at STP = Moles × 22.4 L/mol = 0.2 moles × 22.4 L/mol = 4.48 liters.

3. **Calculate Volume of NO₂**:
- We are given that there are 0.5 moles of NO₂.
- Volume at STP = Moles × 22.4 L/mol = 0.5 moles × 22.4 L/mol = 11.2 liters.

4. **Calculate Moles of CH₄**:
- Given molecules of CH₄ = 6.023 x 10²² molecules.
- Moles of CH₄ = Given molecules / Avogadro's number = 6.023 x 10²² / 6.023 x 10²³ = 0.1 moles.
- Volume at STP = Moles × 22.4 L/mol = 0.1 moles × 22.4 L/mol = 2.24 liters.

5. **Calculate Volume of CO₂**:
- 1 gram molecule of CO₂ is equivalent to 1 mole.
- Volume at STP = 1 mole × 22.4 L/mol = 22.4 liters.

6. **Compare Volumes**:
- SO₂: 4.48 liters
- NO₂: 11.2 liters
- CH₄: 2.24 liters
- CO₂: 22.4 liters

7. **Determine the Maximum Volume**:
- The maximum volume occupied at STP is by CO₂, which is 22.4 liters.

### Final Answer:
The maximum volume at STP is occupied by CO₂ (Carbon Dioxide) with a volume of 22.4 liters.