Home
Class 12
CHEMISTRY
Choose the correct option about followin...

Choose the correct option about following statement.
`S_(1)` : first ionization energy of magesium is less than that aluminium.
`S_(2) : CIO_(3)^(-), CIO_(4)^(-), MnO_(4)^(2-), SO_(4)^(2-), ZnO_(2)^(2-), BO_(3)^(3-)` all these anions have suffix - 'ate'.
`S_(3)` : Increasing order of negative electron gain enthalpy of `17^(th)` group element is `I lt Br lt F lt CI`

A

F T T

B

T T T

C

F F T

D

F T F

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to evaluate the correctness of the three statements provided: ### Statement Analysis: **Statement 1 (S₁):** The first ionization energy of magnesium is less than that of aluminium. 1. **Electronic Configuration:** - Magnesium (Mg) has an atomic number of 12, so its electronic configuration is \(1s^2 2s^2 2p^6 3s^2\). - Aluminium (Al) has an atomic number of 13, so its electronic configuration is \(1s^2 2s^2 2p^6 3s^2 3p^1\). 2. **Ionization Energy Explanation:** - The first ionization energy is the energy required to remove the outermost electron. - In magnesium, the outermost electrons are in the 3s subshell, while in aluminium, the outermost electron is in the 3p subshell. - The 3p electron is farther from the nucleus and experiences a lower effective nuclear charge compared to the 3s electrons. - Therefore, it is easier to remove the 3p electron from aluminium than the 3s electrons from magnesium. **Conclusion for S₁:** This statement is **false**. The first ionization energy of aluminium is less than that of magnesium. --- **Statement 2 (S₂):** ClO₃⁻, ClO₄⁻, MnO₄²⁻, SO₄²⁻, ZnO₂²⁻, BO₃³⁻ all have the suffix 'ate'. 1. **Analyzing the Anions:** - ClO₃⁻ is called chlorate. - ClO₄⁻ is called perchlorate. - MnO₄²⁻ is called manganate. - SO₄²⁻ is called sulfate. - ZnO₂²⁻ is called zincate. - BO₃³⁻ is called borate. **Conclusion for S₂:** This statement is **true**. All these anions have the suffix 'ate'. --- **Statement 3 (S₃):** The increasing order of negative electron gain enthalpy of the 17th group elements is I < Br < F < Cl. 1. **Understanding Electron Gain Enthalpy:** - Electron gain enthalpy is the energy change when an electron is added to an atom. - Generally, as we move up the group in the periodic table, the electron gain enthalpy becomes more negative because the atomic size decreases, leading to a stronger attraction for the added electron. - However, fluorine has a smaller atomic size compared to chlorine, which leads to greater electron-electron repulsion in the compact 2p orbital of fluorine. **Conclusion for S₃:** This statement is **false**. The correct order should be I < Br < Cl < F. --- ### Final Evaluation: - S₁: False - S₂: True - S₃: False Thus, the correct option regarding the statements is **False, True, False**.

To solve the question, we need to evaluate the correctness of the three statements provided: ### Statement Analysis: **Statement 1 (S₁):** The first ionization energy of magnesium is less than that of aluminium. 1. **Electronic Configuration:** - Magnesium (Mg) has an atomic number of 12, so its electronic configuration is \(1s^2 2s^2 2p^6 3s^2\). ...
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the number of reducing agents from the following H_(2)S,SO_(3),CrO_(4)^(2-),Fe^(2+),MnO_(4)^(Θ)

The oxidation states of sulphur in the anions SO_(3)^(2-), S_(2)O_(4)^(2-) , and S_(2)O_(6)^(2-) follow the order

The oxidation states of sulphur in the anions SO_(3)^(2-), S_(2)O_(4)^(2-) , and S_(2)O_(6)^(2-) follow the order

The oxidation states of sulphur in the anions SO_(3)^(2-), S_(2)O_(4)^(2-) , and S_(2)O_(6)^(2-) follow the order

The oxidation states of sulphur in the anions SO_(3)^(2-), S_(2)O_(4)^(2-) , and S_(2)O_(6)^(2-) follow the order

Consider the following reactions : (i) C_(2)O_(4)^(2-) rarr CO_(2) (ii) SO_(4)^(2-) rarr SO_(3)^(2-) (iii) MnO_(4)^(2-) rarr MnO_(4)^(-) (iv) Fe^(3+) rarr Fe^(2+) Choose the correct answer -

How many of these acids are monobasic in nature? H_(2)S, H_(2)O_(2), HCOOH,H_(3)BO_(3),H_(3)PO_(2), HXO_(4), Ph-SO_(3)H

Which of the following statements is/are correct in following reaction. As_(2)S_(5)+NO_(3)^(ɵ)toAsO_(4)^(3-)+NO_(2)+SO_(4)^(2-)

Total number of species that can be oxidzed by acidic permanganate ion (MnO_(4)^(-)//H^(+)) . I^(-),Fe^(2+),CO_(2),C_(2)O_(4)^(2-),S^(2-),SO_(3)^(2-),NO_(2)^(2-),PO_(4)^(3-),SO_(4)^(2-)

Complete the following chemical equation: (i) MnO_(4)^(-)(aq)+S_(2)O_(3)^(2-)(aq)+H_(2)O(I) to (ii) MnO_(4)^(-) +NO_(2)^(-)+H^(+) to