Which of the following molarity values of ions is/are correct for a aqueous solution which contain `5.85% w//v NaCI, 5.55% w//v CaCI_(2)` and `6% w//v NaOH`.

Options

A. `[CI^(-)]=2M`
B. `[Na^(+)]=1M`
C. `[Ca^(2+)]=0.5M`
D. `[OH^(-)]=1.5M`

Explanation

To solve the problem, we need to calculate the molarity of the ions present in the given aqueous solution containing 5.85% w/v NaCl, 5.55% w/v CaCl₂, and 6% w/v NaOH. Here’s a step-by-step breakdown of the calculations:

### Step 1: Calculate the mass of each solute in 100 mL of solution
Assuming we have 100 mL of solution:
- Mass of NaCl = 5.85 g
- Mass of CaCl₂ = 5.55 g
- Mass of NaOH = 6.00 g

### Step 2: Calculate the number of moles of each solute
1. **For NaCl:**
- Molar mass of NaCl = 58.5 g/mol
- Moles of NaCl = Mass / Molar mass = 5.85 g / 58.5 g/mol = 0.1 moles

2. **For CaCl₂:**
- Molar mass of CaCl₂ = 40.08 (Ca) + 2 × 35.45 (Cl) = 110.98 g/mol
- Moles of CaCl₂ = Mass / Molar mass = 5.55 g / 110.98 g/mol ≈ 0.05 moles

3. **For NaOH:**
- Molar mass of NaOH = 22.99 (Na) + 16.00 (O) + 1.01 (H) = 40.00 g/mol
- Moles of NaOH = Mass / Molar mass = 6.00 g / 40.00 g/mol = 0.15 moles

### Step 3: Calculate the molarity of each ion
1. **For Na⁺ ions:**
- Na⁺ comes from both NaCl and NaOH.
- Total moles of Na⁺ = Moles from NaCl + Moles from NaOH = 0.1 + 0.15 = 0.25 moles
- Molarity of Na⁺ = Total moles / Volume (in L) = 0.25 moles / 0.1 L = 2.5 M

2. **For Cl⁻ ions:**
- Cl⁻ comes from NaCl and CaCl₂.
- Total moles of Cl⁻ = Moles from NaCl + 2 × Moles from CaCl₂ = 0.1 + 2 × 0.05 = 0.2 moles
- Molarity of Cl⁻ = Total moles / Volume (in L) = 0.2 moles / 0.1 L = 2.0 M

3. **For Ca²⁺ ions:**
- Ca²⁺ comes only from CaCl₂.
- Total moles of Ca²⁺ = 0.05 moles
- Molarity of Ca²⁺ = Total moles / Volume (in L) = 0.05 moles / 0.1 L = 0.5 M

4. **For OH⁻ ions:**
- OH⁻ comes only from NaOH.
- Total moles of OH⁻ = 0.15 moles
- Molarity of OH⁻ = Total moles / Volume (in L) = 0.15 moles / 0.1 L = 1.5 M

### Summary of Molarities
- Molarity of Na⁺ = 2.5 M
- Molarity of Cl⁻ = 2.0 M
- Molarity of Ca²⁺ = 0.5 M
- Molarity of OH⁻ = 1.5 M

### Step 4: Verify the options
Now, we can check the provided options against our calculated values:
- Cl⁻ = 2.0 M (Correct)
- Na⁺ = 2.5 M (Incorrect if stated as 1 M)
- Ca²⁺ = 0.5 M (Correct)
- OH⁻ = 1.5 M (Correct)

### Conclusion
The correct molarity values for the ions in the solution are:
- Cl⁻: 2.0 M (Correct)
- Ca²⁺: 0.5 M (Correct)
- OH⁻: 1.5 M (Correct)