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The poisson's ratio for O(2) is 1.4. Whi...

The poisson's ratio for `O_(2)` is `1.4`. Which of the following are correct for `O_(2)`?

A

`C_(v) = 5 cal//mol K`

B

`c_(v) or s_(v) = 0.45 cal//mol K`

C

`C_(p)=(R gamma)/(gamma-1)`

D

`C_(v) = (R )/((gamma-1))`

Text Solution

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The correct Answer is:
To solve the problem regarding the Poisson's ratio for \( O_2 \) (oxygen), which is given as \( \gamma = 1.4 \), we need to analyze the implications of this value on the specific heats \( C_p \) and \( C_v \) of the gas. ### Step-by-Step Solution: 1. **Understanding Poisson's Ratio**: The Poisson's ratio (\( \gamma \)) is defined as the ratio of the specific heat at constant pressure (\( C_p \)) to the specific heat at constant volume (\( C_v \)): \[ \gamma = \frac{C_p}{C_v} \] 2. **Using the Relation Between \( C_p \) and \( C_v \)**: We also know the relationship between \( C_p \) and \( C_v \): \[ C_p - C_v = R \] where \( R \) is the ideal gas constant. 3. **Expressing \( C_p \) in Terms of \( C_v \)**: Rearranging the equation gives us: \[ C_p = C_v + R \] Substituting this into the equation for \( \gamma \): \[ \gamma = \frac{C_v + R}{C_v} \] 4. **Simplifying the Equation**: This can be simplified to: \[ \gamma = 1 + \frac{R}{C_v} \] Rearranging gives: \[ \frac{R}{C_v} = \gamma - 1 \] Therefore: \[ C_v = \frac{R}{\gamma - 1} \] 5. **Calculating \( C_v \)**: Given \( \gamma = 1.4 \) and using \( R = 2 \) calorie, we can calculate \( C_v \): \[ C_v = \frac{2}{1.4 - 1} = \frac{2}{0.4} = 5 \text{ calorie per mole Kelvin} \] 6. **Finding \( C_p \)**: Now, we can find \( C_p \): \[ C_p = C_v + R = 5 + 2 = 7 \text{ calorie per mole Kelvin} \] 7. **Verifying the Options**: - **Option A**: \( C_v = 5 \text{ calorie per mole Kelvin} \) - **Correct** - **Option B**: \( C_v = 0.45 \text{ calorie per mole Kelvin} \) - **Incorrect** - **Option C**: \( C_p = \frac{R \gamma}{\gamma - 1} \) - **Correct** (since \( C_p = 7 \text{ calorie per mole Kelvin} \)) - **Option D**: \( C_v = R(\gamma - 1) \) - **Incorrect** (should be \( C_v = \frac{R}{\gamma - 1} \)) ### Conclusion: The correct options are A and C.

To solve the problem regarding the Poisson's ratio for \( O_2 \) (oxygen), which is given as \( \gamma = 1.4 \), we need to analyze the implications of this value on the specific heats \( C_p \) and \( C_v \) of the gas. ### Step-by-Step Solution: 1. **Understanding Poisson's Ratio**: The Poisson's ratio (\( \gamma \)) is defined as the ratio of the specific heat at constant pressure (\( C_p \)) to the specific heat at constant volume (\( C_v \)): \[ \gamma = \frac{C_p}{C_v} ...
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