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How many litres of water must be added t...

How many litres of water must be added to 2 litre aqueous solution of `HCI` with a `pH` of 1 to create an aqueous solution with `pH` of 2 ?

A

`20L`

B

`0.9L`

C

`2L`

D

`18L`

Text Solution

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The correct Answer is:
To solve the problem of how many liters of water must be added to a 2-liter aqueous solution of HCl with a pH of 1 to create an aqueous solution with a pH of 2, we can follow these steps: ### Step 1: Determine the concentration of H⁺ ions in the initial solution (pH = 1) The pH is related to the concentration of hydrogen ions (H⁺) by the formula: \[ \text{pH} = -\log[H^+] \] For pH = 1: \[ [H^+] = 10^{-1} \, \text{M} = 0.1 \, \text{M} \] ### Step 2: Calculate the number of moles of H⁺ in the initial solution Using the concentration and the volume of the solution, we can find the number of moles of H⁺: \[ \text{Moles of } H^+ = [H^+] \times \text{Volume} \] \[ \text{Moles of } H^+ = 0.1 \, \text{M} \times 2 \, \text{L} = 0.2 \, \text{moles} \] ### Step 3: Determine the concentration of H⁺ ions in the final solution (pH = 2) For pH = 2: \[ [H^+] = 10^{-2} \, \text{M} = 0.01 \, \text{M} \] ### Step 4: Set up the equation using the dilution formula We can use the dilution equation \( M_1V_1 = M_2V_2 \), where: - \( M_1 \) = initial concentration of H⁺ = 0.1 M - \( V_1 \) = initial volume of solution = 2 L - \( M_2 \) = final concentration of H⁺ = 0.01 M - \( V_2 \) = final volume of solution (which we need to find) Substituting the known values into the equation: \[ 0.1 \, \text{M} \times 2 \, \text{L} = 0.01 \, \text{M} \times V_2 \] ### Step 5: Solve for \( V_2 \) \[ 0.2 = 0.01 \times V_2 \] \[ V_2 = \frac{0.2}{0.01} = 20 \, \text{L} \] ### Step 6: Calculate the volume of water to be added The final volume of the solution is 20 L, and the initial volume is 2 L. Therefore, the volume of water to be added is: \[ \text{Volume of water} = V_2 - V_1 = 20 \, \text{L} - 2 \, \text{L} = 18 \, \text{L} \] ### Final Answer Thus, **18 liters of water must be added** to the 2-liter aqueous solution of HCl to create an aqueous solution with a pH of 2. ---

To solve the problem of how many liters of water must be added to a 2-liter aqueous solution of HCl with a pH of 1 to create an aqueous solution with a pH of 2, we can follow these steps: ### Step 1: Determine the concentration of H⁺ ions in the initial solution (pH = 1) The pH is related to the concentration of hydrogen ions (H⁺) by the formula: \[ \text{pH} = -\log[H^+] \] For pH = 1: \[ [H^+] = 10^{-1} \, \text{M} = 0.1 \, \text{M} \] ...
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