Number of tertiary bromide of formula `C_(5)H_(11)Br` are `(X)`
number of tertiary bromide of formula `C_(6)H_(13)Br` are `(Y)`
Report your answer as `X + Y`

Explanation

To solve the problem, we need to determine the number of tertiary bromides for the given formulas \(C_5H_{11}Br\) and \(C_6H_{13}Br\), and then sum these values.

### Step-by-Step Solution:

1. **Identify Tertiary Bromides for \(C_5H_{11}Br\)**:
- A tertiary bromide has a carbon atom bonded to three other carbon atoms.
- For the formula \(C_5H_{11}Br\), we can draw the following structure:
- **Structure**:
\[ \text{(CH}_3\text{)}_3CBr \]
This corresponds to 2-bromopentane, where the bromine is attached to a tertiary carbon.
- **Count**: There is only **1** unique structure for \(C_5H_{11}Br\).

\[ X = 1 \]

2. **Identify Tertiary Bromides for \(C_6H_{13}Br\)**:
- For the formula \(C_6H_{13}Br\), we can have several structures:
- **Structure 1**:
\[ \text{CH}_3\text{CH}_2\text{C(CH}_3\text{)}_2Br \]
(2-bromo-3-methylpentane)
- **Structure 2**:
\[ \text{(CH}_3\text{)}_2\text{CHCH}_2\text{CH}_2Br \]
(1-bromo-2-methylpentane)
- **Structure 3**:
\[ \text{(CH}_3\text{)}_3CCH_2Br \]
(2-bromo-2-methylbutane)
- **Structure 4**:
\[ \text{(CH}_3\text{)}_2\text{C(Br)CH}_2\text{CH}_3 \]
(1-bromo-3-methylbutane)
- **Count**: There are **3** unique structures for \(C_6H_{13}Br\).

\[ Y = 3 \]

3. **Calculate Total**:
- Now we sum \(X\) and \(Y\):
\[ X + Y = 1 + 3 = 4 \]

### Final Answer:
\[ \text{The answer is } 4. \]