Home
Class 12
PHYSICS
A force F is applied on a block of mass ...

A force `F` is applied on a block of mass `5 kg` as shown in figure. Co-efficient of friction between the wall and clock is `(sqrt(3))/(2). (g = 10m//s^(2))`

Select correct option(s)

A

Magnitude of minimum force `F` so that block doesn't slip on the wall is `40 N`.

B

Magnitude of minimum force `F` so that block doesn't slip on the wall is `20 N`.

C

If `F lt 40N` then block will side downwards

D

If `F lt 40N` then block will slide upwards

Text Solution

Verified by Experts

The correct Answer is:
A, C
`(F)/(2) + mu(Fsqrt(3)/(2)) = 50`
`rArr (F)/(2) + F xx (3)/(4) = 50 rArr (5F)/(4) = 50 rArr F = 40N`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • TEST PAPERS

    RESONANCE ENGLISH|Exercise PHYSICS|784 Videos

  • TEST PAPERS

    RESONANCE ENGLISH|Exercise PART - II PHYSICS SEC - 2|20 Videos

  • SIMPLE HARMONIC MOTION

    RESONANCE ENGLISH|Exercise Advanced Level Problems|13 Videos

  • TEST SERIES

    RESONANCE ENGLISH|Exercise PHYSICS|130 Videos

Similar Questions

Explore conceptually related problems

A force F" is applied on a block of mass 5 kg as shown in figure. Co-efficient of friction between the wall and clock is (sqrt(3))/(2). (g = 10m//s^(2)) If 'f_(1)" and 'f_(2)' are magnitude of frictional force on the block when F = 40 N and F = 140 N repesctively. Then choose correct options

A force of 100 N is applied on a block of mass 3 kg as shown in figure. The coefficient of friction between the surface and the block is 1/4 .Then the friction force acting on the block is

Knowledge Check

  • A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4. A force F of 3 N is applied on the block as shown in figure. The force of friction between the block and the floor is (Take g=10 m s^(-2) )

    A
    3 N
    B
    8 N
    C
    4 N
    D
    6 N

    • Similar Questions

    Explore conceptually related problems

    A force of 100 N is applied on a block of mass 3kg as shown below. The coefficient of friction between wall and the block is 1//4 . The friction force acting on the block is :

    Two block A and B of mass 50 kg and 300 kg respectively are placed as shown in figure. Coefficient of friction between all surface is (1)/(2) Then (take g = 10 m//s )

    A block of mass m is placed on another block of mass M lying on a smooth horizontal surface as shown in the figure. The co-efficient of friction between the blocks is mu . Find the maximum horizontal force F (in Newton) that can be applied to the block M so that the blocks together with same acceleration? (M=3kg, m=2kg, mu=0.1, g=10m//s^(2))

    A force F=75 N is applied on a block of mass 5 kg along the fixed smooth incline as as shown in the figure. Here gravitational acceleration g = 10 m s^(-2) . The acceleration of the block is

    A bolck of mass m =2 kg is placed on a plank of mass M = 10 kg, which is placed on a smooth horizontal plane as shown in the figure. The coefficient of friction between the block and the plank is mu=(1)/(3) . If a horizontal force F is applied on the plank, then the maximum value of F for which the block and the plank move together is (g=10m//s^(2))

    Block A of mass 3 kg is placed on another block B of mass 5 kg placed on the smooth surface. If coefficient of friction between two blocks is 1/2 and 32 N force is applied on block B as shown in the figure, then the work done by the frictional force on block A in first two second will be (initial velocity of the system is zero and g = 10 m/s^2 )

    A block B is pulled by a force of 18 N applied to a light pulley as shown in the figure. If the coefficient of friction is 0.4 and the acceleration of the block is 0.5 ms^(-2) , the mass of the block is (g = 10 m//s^2)

    Home
    Profile