A block of mass `m` is placed at rest on a smooth wedge of mass M placed at rest on a smooth horizontal surface. As the system is released

Options

A. path of centre of mass of system (block `+` wedge) is parabolic
B. path of centre of mass of system (block `+` wedge) is straight line.
C. normal force acting on the wedge from the ground is `(4mg)/(3)`
D. normal force acting on the wedge from the ground is `2mg`

Answer

B, C

Explanation

`:'` Net force is vertically downwards on system
`a_(cm) = (m xx (2g)/(3))/(m+m) = (g)/(3)`