When a sample of `N_(2)` gas is passed through a liquid (`N_(2)` is insoluble in the liquid) part of the liquid vaporises and these vapors are carride off with the `N_(2)` gas. It ws found that under identical conditions of `T` & `P`, vapour density of wet `N_(2)` is higher than that of dry `N_(2)`.
Liquid through which `N_(2)` gas was passed can be [assume `N_(2)` to be insoluble in all]:

Options

A. `C_(6)H_(5)OH`
B. `CHCl_(3)`
C. `C_(2)H_(5)OH`
D. `H_(2)O`

Answer

To solve the problem, we need to analyze the information provided and deduce which liquid could have caused the vapor density of wet \( N_2 \) to be higher than that of dry \( N_2 \).

### Step-by-Step Solution:

1. **Understanding Vapor Density**:
- Vapor density is defined as the mass of a certain volume of gas compared to the mass of an equal volume of hydrogen at the same temperature and pressure. When \( N_2 \) gas is passed through a liquid, if the vapor density of the resulting mixture (wet \( N_2 \)) is higher than that of dry \( N_2 \), it indicates that the liquid has contributed to the mass of the vapor.

**Hint**: Remember that vapor density increases if additional mass (from vaporized liquid) is added to the gas mixture.

2. **Insolubility of \( N_2 \)**:
- Since \( N_2 \) is stated to be insoluble in the liquid, this means that the gas does not dissolve in the liquid but can carry off the vapor of the liquid when it vaporizes.

**Hint**: Consider liquids that do not react with or dissolve \( N_2 \).

3. **Identifying Possible Liquids**:
- The problem suggests that the liquid must be a hydrocarbon or a similar compound that can vaporize easily without reacting with \( N_2 \).

**Hint**: Focus on liquids that are known to be hydrocarbons or have similar properties.

4. **Analyzing the Options**:
- The options provided include various hydrocarbons. Since \( N_2 \) does not react with water, we can eliminate water as a possible liquid. The remaining options should be evaluated based on their ability to vaporize and contribute to the vapor density.

**Hint**: Look for hydrocarbons that are likely to vaporize under the conditions given.

5. **Conclusion**:
- After evaluating the options, we conclude that the liquid through which \( N_2 \) gas was passed must be a hydrocarbon that can vaporize and increase the vapor density of the gas mixture. Thus, the answer would include hydrocarbons such as \( C_6H_5OH \) (phenol), \( CHCl_3 \) (chloroform), and \( C_2H_5OH \) (ethanol).

**Final Answer**: The liquid through which \( N_2 \) gas was passed can be assumed to be hydrocarbons like \( C_6H_5OH \), \( CHCl_3 \), and \( C_2H_5OH \).