The depletion layer in diode is `1 mum` wide and the knee potential is `0.6 V`, then the electric field in the depletion layer will be

Options

A. zero
B. `0.6Vm^(-1)`
C. `6xx10^(4) V//m`
D. `6xx10^(5) V//m`

Explanation

To find the electric field in the depletion layer of a diode, we can use the relationship between electric field (E), potential difference (V), and width of the depletion layer (L). The formula for electric field is given by:

\[ E = \frac{V}{L} \]

### Step-by-Step Solution:

1. **Identify the given values:**
- Width of the depletion layer, \( L = 1 \, \mu m = 1 \times 10^{-6} \, m \)
- Knee potential, \( V = 0.6 \, V \)

2. **Substitute the values into the formula for electric field:**
\[ E = \frac{V}{L} \]
\[ E = \frac{0.6 \, V}{1 \times 10^{-6} \, m} \]

3. **Calculate the electric field:**
\[ E = 0.6 \times 10^{6} \, V/m \]
\[ E = 6 \times 10^{5} \, V/m \]

4. **Final Result:**
The electric field in the depletion layer is \( 6 \times 10^{5} \, V/m \).