The pressure of an ideal gas is written as `p=(2E)/(3V)`.Here `E` refers to

Options

A. average translational kinetic energy
B. rotational kinetic energy
C. total kinetic energy
D. None of these

Explanation

To solve the question, we need to analyze the given equation for the pressure of an ideal gas:

**Step 1: Understand the equation given**
The equation provided is \( p = \frac{2E}{3V} \), where \( p \) is the pressure, \( E \) is some form of energy, and \( V \) is the volume of the gas.

**Step 2: Recall the relationship between pressure and kinetic energy in gases**
In the kinetic theory of gases, the pressure exerted by an ideal gas is related to the average kinetic energy of the gas molecules. The pressure can be derived from the translational kinetic energy of the gas molecules.

**Step 3: Identify the type of kinetic energy**
The average kinetic energy of gas molecules due to their translational motion is given by the formula:
\[ E_{trans} = \frac{3}{2} k_B T \]
where \( k_B \) is the Boltzmann constant and \( T \) is the temperature. Since the pressure is directly related to the translational kinetic energy, we can conclude that \( E \) in the equation \( p = \frac{2E}{3V} \) refers to the average translational kinetic energy of the gas molecules.

**Step 4: Analyze the options provided**
The options given are:
1. Average translational kinetic energy
2. Rotational kinetic energy
3. Total kinetic energy
4. None of these

Since we have established that \( E \) corresponds to the average translational kinetic energy, the correct answer is option 1.

**Final Answer:**
The correct answer is **Average translational kinetic energy**.

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