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When a system is taken from state 'a' to state 'b' along the path 'acd', is is found that a quantity of heat `Q = 200J` is absorbed by the system and a work `W = 80 J` is done by it. Along the path 'adb', `Q = 144J`. The work done along the path 'adb' is

A

`6J`

B

`12 J`

C

`18 J`

D

`24 J`

Text Solution

Verified by Experts

The correct Answer is:
D
`DeltaU =` same is both process.
`Q_(acd) - W_(acd) = Q_(adb) - W_(adb)`
`200 - 80 = 144 - W_(adb) W_(adb) = 24J`
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