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For two thermodynamic process temperatur...

For two thermodynamic process temperature and volume diagram are given. In first process, it is a straight line having initial and final coordinates as `(V_(0),T_(0))` and `(2V_(0), 2T_(0))`, where as in second process it is a rectangular hyperbola having intial and final coordinates `(V_(0),T_(0))` and `(2V_(0), T_(0)//2)`. Then ratio of work doen in the two process must be

A

`1 : 2`

B

`2 : 1`

C

`1 : 1`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
First process is constant pressure
Hence, `W_(1) = nR (2T_(0) -T_(0)) = nRT_(0)`
Equation of second process is `T = (c )/(V)`
Hence, `P = (nRT)/(V) = (nRC)/(V^(2))`

`W_(2) = int_(V_(0))^(2V_(0)) PdV = (nRT_(0))/(2)`
`(W_(1))/(W_(2)) = 2:1`
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